However, the explanation provided would suggest otherwise, that there are different hybridized orbitals of different energies at different portions of a single hybridized atom excluding lone pairs.
I understand those being non-hybridized in a hybridized atom. Thus, my question is how the hybrid argument that was presented works and how would one be able to realize the different hybridized states of an atom in a molecule as an approximation. Older textbooks decided to use a d-orbital formalism for elements of the third and lower in the periodic table periods to explain hyperconjugation.
Nowadays, most of these compounds are explained with multi-centre bonds. The resulting three orbitals will thereby create a four-electron three-centre bond. The greater the order the shorter the bond so the smaller the order the longer the bond — and there you have your result.
Sign up to join this community. The best answers are voted up and rise to the top. Stack Overflow for Teams — Collaborate and share knowledge with a private group. As axial is repelled more it gets farther and the bond length increases. All rights reserved. Classscience » Chemistry. Chemical Bonding and Molecular Structure. Share with your friends. Surbhi Roy answered this. I am constantly working to make authentic and reliable information to be shared with my students and widen the horizons of knowledge.
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